2025/12/12

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2025-12-12 12:16:06 +0100 <lucabtz> i think rank N means it has rank N-1 as its arguments, the base case rank 0 being a monomorphic value/function
2025-12-12 12:15:15 +0100trickard_(~trickard@cpe-83-98-47-163.wireline.com.au)
2025-12-12 12:15:05 +0100 <Enrico63> I kind of get that. I suppose I want to do a quiz to make sure I have truly understood, rather than memoized some patterns
2025-12-12 12:13:44 +0100 <Enrico63> Whereas rank 2 means that the implementation (i.e. the inner scope) chooses the type variable of the inner forall
2025-12-12 12:12:39 +0100 <haskellbridge> <loonycyborg> With rank 1 all variables are set at outer scope and you won't be passing any polymorphic functions.
2025-12-12 12:12:37 +0100 <Enrico63> loonycyborg, yeah, I'm also (halfway) there
2025-12-12 12:12:31 +0100trickard(~trickard@cpe-83-98-47-163.wireline.com.au) (Read error: Connection reset by peer)
2025-12-12 12:12:08 +0100 <haskellbridge> <loonycyborg> I personally found the trick to understanding rank-n is that they're about polymorphic functions that can take other polymorphic functions.
2025-12-12 12:12:00 +0100merijn(~merijn@host-vr.cgnat-g.v4.dfn.nl) (Ping timeout: 245 seconds)
2025-12-12 12:10:10 +0100 <mauke> (the answer is yes)
2025-12-12 12:09:41 +0100 <Enrico63> Yeah, I don't quite get what's unclear to me, so I asked those previous questions to have something to hinge on
2025-12-12 12:08:52 +0100 <mauke> well, it's what I would've used to answer your question :-)
2025-12-12 12:07:52 +0100 <Enrico63> I come _from_ that page
2025-12-12 12:07:01 +0100 <mauke> https://wiki.haskell.org/Rank-N_types
2025-12-12 12:06:09 +0100 <Enrico63> It is rank 2, correct?
2025-12-12 12:06:02 +0100 <Enrico63> Well, that's the same as `forall b. (forall a. a -> a) -> b`
2025-12-12 12:05:37 +0100 <Enrico63> (Be damned the formatting, ahhah)
2025-12-12 12:05:25 +0100 <Enrico63> Instead, if I have `(forall a. a -> a) -> b`, that's rank 2, right?
2025-12-12 12:03:53 +0100 <lucabtz> yes rank 1
2025-12-12 12:02:08 +0100 <Enrico63> The id function has type `forall a. a -> a` which is rank 1, right?
2025-12-12 12:02:07 +0100 <Enrico63> Hi, there. I'd like some clarification on rank-n types.
2025-12-12 12:00:40 +0100Enrico63(~Enrico63@host-95-251-99-143.retail.telecomitalia.it) Enrico63
2025-12-12 11:52:30 +0100Katarushisu(~Katarushi@finc-20-b2-v4wan-169598-cust1799.vm7.cable.virginm.net) (Ping timeout: 244 seconds)
2025-12-12 11:44:50 +0100tromp(~textual@2001:1c00:3487:1b00:dd4:56d:fd02:60e2)
2025-12-12 11:42:56 +0100tromp(~textual@2001:1c00:3487:1b00:dd4:56d:fd02:60e2) (Quit: My iMac has gone to sleep. ZZZzzz…)
2025-12-12 11:38:15 +0100 <gentauro> related xD https://xkcd.com/2453/
2025-12-12 11:37:47 +0100merijn(~merijn@host-vr.cgnat-g.v4.dfn.nl) merijn
2025-12-12 11:27:55 +0100Tuplanolla(~Tuplanoll@91-152-225-194.elisa-laajakaista.fi) Tuplanolla
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2025-12-12 11:24:55 +0100merijn(~merijn@host-vr.cgnat-g.v4.dfn.nl) (Ping timeout: 240 seconds)
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2025-12-12 11:14:25 +0100lucabtz(~lucabtz@user/lucabtz) lucabtz
2025-12-12 11:14:14 +0100lucabtz(~lucabtz@user/lucabtz) (Quit: leaving)
2025-12-12 11:09:41 +0100poscat(~poscat@user/poscat) poscat
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2025-12-12 11:04:59 +0100lucabtz(~lucabtz@user/lucabtz) lucabtz
2025-12-12 11:03:55 +0100trickard_(~trickard@cpe-83-98-47-163.wireline.com.au)
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2025-12-12 11:02:29 +0100__monty__(~toonn@user/toonn) toonn
2025-12-12 11:02:00 +0100humasect(~humasect@dyn-192-249-132-90.nexicom.net) humasect
2025-12-12 10:57:43 +0100xff0x(~xff0x@fsb6a9491c.tkyc517.ap.nuro.jp) (Ping timeout: 240 seconds)
2025-12-12 10:57:35 +0100poscat(~poscat@user/poscat) (Ping timeout: 240 seconds)
2025-12-12 10:57:11 +0100poscat0x04(~poscat@user/poscat) poscat
2025-12-12 10:56:49 +0100Googulator(~Googulato@team.broadbit.hu)
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