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| 2025-02-07 11:37:47 +0100 | JuanDaugherty | ColinRobinson |
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| 2025-02-07 11:32:20 +0100 | akegalj | (~akegalj@141-136-207-93.dsl.iskon.hr) (Ping timeout: 244 seconds) |
| 2025-02-07 11:32:20 +0100 | ubert | (~Thunderbi@2a02:8109:ab8a:5a00:3bd7:f04:27ee:5a69) ubert |
| 2025-02-07 11:32:05 +0100 | <tomsmeding> | somehow :) |
| 2025-02-07 11:31:57 +0100 | <tomsmeding> | I think you can do the same in ocaml |
| 2025-02-07 11:31:46 +0100 | <tomsmeding> | in haskell, you can't satisfy that Ord constraint unless you know what the 'k' type is, monomorphically, or unless you have that 'k' as a parameter yourself and get the Ord instance from your caller |
| 2025-02-07 11:31:24 +0100 | JuanDaugherty | (~juan@user/JuanDaugherty) JuanDaugherty |
| 2025-02-07 11:31:19 +0100 | alp | (~alp@2001:861:8ca0:4940:41b4:15ba:b9c5:e001) |
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| 2025-02-07 11:30:04 +0100 | remedan | (~remedan@ip-62-245-108-153.bb.vodafone.cz) remedan |
| 2025-02-07 11:27:53 +0100 | remedan | (~remedan@ip-62-245-108-153.bb.vodafone.cz) (Quit: Bye!) |
| 2025-02-07 11:27:35 +0100 | misterfish | (~misterfis@31-161-39-137.biz.kpn.net) misterfish |
| 2025-02-07 11:27:01 +0100 | <tomsmeding> | the types look different, but as you say, ocaml is the one that's more flexible, not haskell |
| 2025-02-07 11:26:44 +0100 | <tomsmeding> | I'm not sure it can! That's my point |
| 2025-02-07 11:26:36 +0100 | <neiluj> | sure, thanks! just wanted to see if haskell could solve my problem more easily, and it seems so :) |
| 2025-02-07 11:26:16 +0100 | <tomsmeding> | wherever you export your t, also make sure that module exports a compare function |
| 2025-02-07 11:25:56 +0100 | <neiluj> | plus it's more explicit, so easier to know which function gets called |
| 2025-02-07 11:25:54 +0100 | <tomsmeding> | you might need to visit some ocaml-specific forum to ask for more specific guidance. But I think you can get what you want in ocaml :) |
| 2025-02-07 11:25:35 +0100 | <tomsmeding> | right |
| 2025-02-07 11:25:34 +0100 | <neiluj> | for that type |
| 2025-02-07 11:25:28 +0100 | <neiluj> | given a type t, in ocaml, i can implement to instances of Ord with different comparison functions |
| 2025-02-07 11:24:48 +0100 | <neiluj> | well ocaml functors are more flexible as you can implement multiple instances of a module type for some type, while in haskell you'd need a newtype |
| 2025-02-07 11:24:05 +0100 | <neiluj> | instead of f :: Ord t => t -> t (where the Ord is implicit in the function call) |
| 2025-02-07 11:22:57 +0100 | <neiluj> | for ex: val f : (type t) (module Ord with type t = t) -> t -> t |