Newest at the top
| 2025-12-03 20:58:24 +0100 | <tomsmeding> | (credit doesn't go to me though) |
| 2025-12-03 20:58:12 +0100 | <tomsmeding> | Leary: it turns out `NOINLINE [0]` yields the desired behaviour, at least on 9.8, 9.10, 9.12 and the 9.14 RC |
| 2025-12-03 20:55:48 +0100 | spew | (~spew@user/spew) (Quit: WeeChat 4.7.2) |
| 2025-12-03 20:47:17 +0100 | trickard_ | trickard |
| 2025-12-03 20:44:57 +0100 | Googulator | (~Googulato@2a01-036d-0106-479c-d9ec-010d-f188-ffcb.pool6.digikabel.hu) |
| 2025-12-03 20:44:09 +0100 | Googulator | (~Googulato@2a01-036d-0106-479c-d9ec-010d-f188-ffcb.pool6.digikabel.hu) (Quit: Client closed) |
| 2025-12-03 20:35:47 +0100 | Googulator | (~Googulato@2a01-036d-0106-479c-d9ec-010d-f188-ffcb.pool6.digikabel.hu) |
| 2025-12-03 20:35:40 +0100 | Googulator | (~Googulato@2a01-036d-0106-479c-d9ec-010d-f188-ffcb.pool6.digikabel.hu) (Quit: Client closed) |
| 2025-12-03 20:34:58 +0100 | Lord_of_Life | (~Lord@user/lord-of-life/x-2819915) Lord_of_Life |
| 2025-12-03 20:31:12 +0100 | <haskellbridge> | <Zemyla> I'm not sure, but I think it'd even mean that liftA2 coerce = coerce (<*>). |
| 2025-12-03 20:29:15 +0100 | Lord_of_Life | (~Lord@user/lord-of-life/x-2819915) (Ping timeout: 240 seconds) |
| 2025-12-03 20:29:11 +0100 | <yin> | grinds my gears |
| 2025-12-03 20:28:20 +0100 | <EvanR> | yes |
| 2025-12-03 20:28:07 +0100 | <yin> | the inner ones |
| 2025-12-03 20:27:54 +0100 | <yin> | aren't those parenthesis redundant? |
| 2025-12-03 20:27:43 +0100 | <lambdabot> | Monad ((->) w) => (w -> (w -> a)) -> w -> a |
| 2025-12-03 20:27:39 +0100 | <yin> | @type join @((->) _) |
| 2025-12-03 20:26:10 +0100 | <haskellbridge> | <Zemyla> Okay, so it is true. |
| 2025-12-03 20:23:24 +0100 | ft | (~ft@p508db844.dip0.t-ipconnect.de) ft |
| 2025-12-03 20:16:41 +0100 | Googulator | (~Googulato@2a01-036d-0106-479c-d9ec-010d-f188-ffcb.pool6.digikabel.hu) |
| 2025-12-03 20:13:44 +0100 | <Leary> | Boiling down to `fmap coerce = coerce`. |
| 2025-12-03 20:13:04 +0100 | <Leary> | Let g = k = coerce @a @b; h = f = id @a. This satisfies the precondition, giving us: fmap (coerce @a @b) . liftCoercion (coerce @a @a) = coerce @(F a) @(F b) . fmap (id @a) |
| 2025-12-03 20:12:24 +0100 | <lambdabot> | g . h = k . f => $map_F g . liftCoercion h = liftCoercion k . $map_F f |
| 2025-12-03 20:12:24 +0100 | <Leary> | @free liftCoercion :: (a -> b) -> F a -> F b |
| 2025-12-03 20:12:11 +0100 | <Leary> | Zemyla: Say we have `Functor F` with `type role F representational`. That means we have `forall a b. Coercible a b => Coercible (F a) (F b)`. `Coercible` can be modeled as an implicit `->` restricted to canonical no-ops, so (ignoring the other direction) this corresponds to a `liftCoercion :: (a -> b) -> F a -> F b` function operating on the restricted domain. |
| 2025-12-03 20:10:19 +0100 | lambda_gibbon | (~lambda_gi@208.83.175.39) (Ping timeout: 260 seconds) |
| 2025-12-03 20:07:41 +0100 | trickard_ | (~trickard@cpe-85-98-47-163.wireline.com.au) |
| 2025-12-03 20:07:28 +0100 | trickard_ | (~trickard@cpe-85-98-47-163.wireline.com.au) (Read error: Connection reset by peer) |
| 2025-12-03 20:03:15 +0100 | ljdarj1 | ljdarj |
| 2025-12-03 20:03:15 +0100 | ljdarj | (~Thunderbi@user/ljdarj) (Ping timeout: 240 seconds) |
| 2025-12-03 20:01:45 +0100 | ljdarj1 | (~Thunderbi@user/ljdarj) ljdarj |
| 2025-12-03 19:49:56 +0100 | CiaoSen | (~Jura@2a02:8071:64e1:da0:5a47:caff:fe78:33db) CiaoSen |
| 2025-12-03 19:49:01 +0100 | vanishingideal | (~vanishing@user/vanishingideal) vanishingideal |
| 2025-12-03 19:48:48 +0100 | humasect | (~humasect@dyn-192-249-132-90.nexicom.net) (Remote host closed the connection) |
| 2025-12-03 19:47:48 +0100 | <tomsmeding> | which sounds like it _ought_ to be true, but I don't know what to conclude that from |
| 2025-12-03 19:46:11 +0100 | euphores | (~SASL_euph@user/euphores) (Quit: Leaving.) |
| 2025-12-03 19:45:33 +0100 | <tomsmeding> | so it sounds like you're asking: if f's argument is representational, do we have `fmap coerce x = coerce x` for `x :: f (a -> b)` |
| 2025-12-03 19:44:24 +0100 | <tomsmeding> | well, `liftA2 f x y = f <$> x <*> y` is a law |
| 2025-12-03 19:42:46 +0100 | <haskellbridge> | <Zemyla> If f is representational and Applicative, then does that necessarily imply that liftA2 coerce a b = coerce a <*> b? |
| 2025-12-03 19:37:36 +0100 | ouilemur | (~jgmerritt@user/ouilemur) ouilemur |
| 2025-12-03 19:34:22 +0100 | skum | (~skum@user/skum) skum |
| 2025-12-03 19:33:59 +0100 | skum | (~skum@user/skum) (Quit: WeeChat 4.7.2) |
| 2025-12-03 19:31:52 +0100 | ljdarj | (~Thunderbi@user/ljdarj) ljdarj |
| 2025-12-03 19:31:25 +0100 | Anarchos | (~Anarchos@91-161-254-16.subs.proxad.net) () |
| 2025-12-03 19:27:33 +0100 | target_i | (~target_i@user/target-i/x-6023099) target_i |
| 2025-12-03 19:25:53 +0100 | <__monty__> | tomsmeding: That part of the structure is necessary. Ordering of the elements is significant. |
| 2025-12-03 19:23:52 +0100 | trickard_ | (~trickard@cpe-85-98-47-163.wireline.com.au) |
| 2025-12-03 19:23:46 +0100 | machinedgod | (~machinedg@d75-159-126-101.abhsia.telus.net) machinedgod |
| 2025-12-03 19:23:38 +0100 | trickard_ | (~trickard@cpe-85-98-47-163.wireline.com.au) (Read error: Connection reset by peer) |
| 2025-12-03 19:18:11 +0100 | mulk | (~mulk@pd9514972.dip0.t-ipconnect.de) mulk |