2024/10/27

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2024-10-27 22:23:50 +0100Everything(~Everythin@178-133-204-231.mobile.vf-ua.net) Everything
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2024-10-27 21:47:19 +0100peterbecich(~Thunderbi@syn-047-229-123-186.res.spectrum.com) peterbecich
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2024-10-27 21:27:27 +0100tromp(~textual@92-110-219-57.cable.dynamic.v4.ziggo.nl)
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2024-10-27 21:18:37 +0100swistak(~swistak@185.21.216.141)
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2024-10-27 21:14:37 +0100merijn(~merijn@128-137-045-062.dynamic.caiway.nl) merijn
2024-10-27 21:13:05 +0100 <tomsmeding> I guess there's still the possibility of writing insertion sort, but that's not necessarily easier than the proper linear solution
2024-10-27 21:12:53 +0100ljdarj1ljdarj
2024-10-27 21:12:53 +0100ljdarj(~Thunderbi@user/ljdarj) (Ping timeout: 245 seconds)
2024-10-27 21:12:37 +0100 <tomsmeding> ah :)
2024-10-27 21:12:18 +0100 <monochrom> Oh haha this was more fun. The question already defined "sort xs = unwrap (foldMap sing xs)". So the door was closed.
2024-10-27 21:10:04 +0100ljdarj1(~Thunderbi@user/ljdarj) ljdarj
2024-10-27 21:06:01 +0100 <monochrom> I forgot. Let me check the marking scheme I wrote.
2024-10-27 21:05:50 +0100 <Rembane> Just gotta have the right sorting function!
2024-10-27 21:05:26 +0100 <int-e> (because of how sort is implemented)
2024-10-27 21:05:26 +0100 <tomsmeding> cute :)
2024-10-27 21:05:15 +0100 <tomsmeding> yes
2024-10-27 21:05:12 +0100 <int-e> tomsmeding: the irony there is... if a and b are sorted, that'll be O(n)
2024-10-27 21:05:04 +0100 <tomsmeding> I guess that's actually linear with Haskell's sort function
2024-10-27 21:04:49 +0100 <tomsmeding> (such as: \a b -> sort (a ++ b))