2024/09/25

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2024-09-25 03:38:50 +0200Smiles(uid551636@id-551636.lymington.irccloud.com) (Quit: Connection closed for inactivity)
2024-09-25 03:38:45 +0200 <EvanR> microwaves, nanowaves, picowaves
2024-09-25 03:37:46 +0200 <geekosaur> err, prefixes
2024-09-25 03:37:41 +0200 <geekosaur> then they just gave up and switched to Greek suffixes
2024-09-25 03:37:09 +0200 <geekosaur> that made perfect sense until they figured out how to generate and control microwave frequencies
2024-09-25 03:36:16 +0200 <monochrom> Err, s/HS/HF/ # VHF, UHF
2024-09-25 03:35:49 +0200ystael(~ystael@user/ystael) (Ping timeout: 248 seconds)
2024-09-25 03:35:32 +0200 <monochrom> haha
2024-09-25 03:34:54 +0200 <geekosaur> overshoe_{\omega}
2024-09-25 03:34:27 +0200 <EvanR> that's why the layers are indexed by an ordinal
2024-09-25 03:34:05 +0200 <monochrom> I mean, if you start having two layers of overshoes, the outer layer would have to be called something like "ultrashoes" or something ridiculous and soon you will run out of superlatives.
2024-09-25 03:34:05 +0200morb(~morb@pool-108-41-100-120.nycmny.fios.verizon.net) (Remote host closed the connection)
2024-09-25 03:33:57 +0200 <EvanR> highspeed CMOS
2024-09-25 03:33:57 +0200merijn(~merijn@204-220-045-062.dynamic.caiway.nl) merijn
2024-09-25 03:33:09 +0200 <monochrom> The "VHS, UHS, HD, UHD, VVVVUUUUHD" progression applies.
2024-09-25 03:32:37 +0200 <monochrom> I don't suppose you would put on two layers of overshoes?
2024-09-25 03:32:01 +0200geekosaurwonders where overshoes fit here 😛
2024-09-25 03:31:55 +0200 <haskellbridge> <Bowuigi> You could use two shirts as an example instead
2024-09-25 03:31:50 +0200 <EvanR> left leg and right leg
2024-09-25 03:31:43 +0200 <EvanR> two pants
2024-09-25 03:31:32 +0200 <monochrom> mom used to advise "it's winter, put on two pants". (I declined.)
2024-09-25 03:31:22 +0200 <EvanR> not even people who wear sandals and socks do that
2024-09-25 03:31:02 +0200 <monochrom> I think some people do that.
2024-09-25 03:30:47 +0200 <monochrom> OK fine! :)
2024-09-25 03:30:42 +0200 <EvanR> lol
2024-09-25 03:30:40 +0200 <monochrom> :(
2024-09-25 03:30:33 +0200 <haskellbridge> <Bowuigi> Unless you are used to putting socks on top of your shoes
2024-09-25 03:30:11 +0200 <haskellbridge> <Bowuigi> The socks example was an example of a groupoid rather than a group
2024-09-25 03:29:46 +0200 <EvanR> \o/
2024-09-25 03:29:33 +0200 <haskellbridge> <Bowuigi> It does tho
2024-09-25 03:28:37 +0200 <EvanR> shouldn't the same theorem apply to groupoids
2024-09-25 03:28:36 +0200 <monochrom> Right, without commutativity, the undo of "put on socks, put on shoes" is not "take off socks, take off shoes".
2024-09-25 03:28:23 +0200 <EvanR> a group is like a groupoid where all the objects are the same
2024-09-25 03:28:21 +0200morb(~morb@pool-108-41-100-120.nycmny.fios.verizon.net)
2024-09-25 03:28:00 +0200 <EvanR> I know how it's too specific
2024-09-25 03:27:53 +0200 <EvanR> waaaaaaaaait
2024-09-25 03:27:49 +0200morb(~morb@pool-108-41-100-120.nycmny.fios.verizon.net) (Remote host closed the connection)
2024-09-25 03:26:42 +0200 <EvanR> that formula makes way more sense now, ignoring the mathematical proof of it, after thinking of it like invertible functions. If you want to invert "do b, then do a to the product of that", you have to first undo a then undo b
2024-09-25 03:23:00 +0200merijn(~merijn@204-220-045-062.dynamic.caiway.nl) (Ping timeout: 252 seconds)
2024-09-25 03:22:04 +0200xff0x(~xff0x@fsb6a9491c.tkyc517.ap.nuro.jp)
2024-09-25 03:20:12 +0200 <EvanR> that's cool
2024-09-25 03:19:08 +0200 <Lears> Ah, no; with identity that's not even a weakening: a * (b * c) = (1 * a) * (b * c) = 1 * ((a * b) * c) = (a * b) * c
2024-09-25 03:18:10 +0200merijn(~merijn@204-220-045-062.dynamic.caiway.nl) merijn
2024-09-25 03:17:05 +0200 <monochrom> You have used identity, inverse, associativity. So I say yes, you pretty much need a group.
2024-09-25 03:16:39 +0200 <Lears> Groups are pretty general; they only have a few laws. You're already using identity, invertibility and associativity---that's all of them. I suppose you could weaken associativity to `(w * x) * (y * z) = w * ((x * y) * z)`, but I doubt that gives you anything of interest.
2024-09-25 03:11:49 +0200 <EvanR> i.e. is group laws too specific
2024-09-25 03:11:36 +0200 <EvanR> this is a theorem about groups, but does it only work for groups?
2024-09-25 03:11:17 +0200 <EvanR> QED
2024-09-25 03:11:14 +0200 <EvanR> (ab)⁻¹ = b⁻¹a⁻¹
2024-09-25 03:11:11 +0200 <EvanR> 1 = abb⁻¹a⁻¹ (obviously)