2024/09/21

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2024-09-21 22:21:02 +0200 <tuxpaint> gomaxprocs does not determine the max amount of system threads
2024-09-21 22:21:01 +0200 <tomsmeding> it's not like that `syscall` instruction can magically go off and run asynchronously
2024-09-21 22:20:55 +0200 <tuxpaint> you can launch another thread and do work, you are not frozen
2024-09-21 22:20:55 +0200 <geekosaur> no? it fires off completely separate threads for that
2024-09-21 22:20:39 +0200 <tomsmeding> fine, but you still have a thread less for "normal" go code!
2024-09-21 22:20:26 +0200 <geekosaur> the IO manager manages them separately from standard threads
2024-09-21 22:20:12 +0200 <tomsmeding> ... okay, but the thread is still blocked and can't do anything else
2024-09-21 22:20:03 +0200 <geekosaur> like ghc's IO manager threads
2024-09-21 22:19:58 +0200 <geekosaur> right
2024-09-21 22:19:51 +0200 <tuxpaint> the runtime does not see that thread as a thread that is "working"
2024-09-21 22:19:45 +0200 <tomsmeding> so something is contradictory here
2024-09-21 22:19:39 +0200 <geekosaur> (ghc ensures the C RTS is set up, but go's pure-go approach means it probably isn't and going through libc will therefore be dangerous)
2024-09-21 22:19:31 +0200 <tomsmeding> tuxpaint: if you perform a syscall, your thread is blocked
2024-09-21 22:19:26 +0200 <tuxpaint> and it doesn't take up when waiting, one of your gomaxprocs slots
2024-09-21 22:19:11 +0200 <tuxpaint> while the pure-go syscall, they can unblock the worker and do something else while the syscall is waiting
2024-09-21 22:19:00 +0200 <geekosaur> other things that come up are C-style global constructors/destructors and things that look like syscalls but aren't directly and may use services like malloc which could well fail with the go runtime because the C runtime isn't initialized
2024-09-21 22:18:21 +0200 <tuxpaint> in go there is gomaxprocs, so each blocking thread takes a slot from gomaxprocs. say you have 20 slots, a cgo call will take one of those 20 slots when invoked, and cannot unblock the worker.
2024-09-21 22:17:57 +0200 <geekosaur> I assume go's stdlib is wired to a particular kernel ABI and doesn't need the runtime checks
2024-09-21 22:17:50 +0200 <tomsmeding> sure, but tuxpaint is claiming that there is more than just speed
2024-09-21 22:17:31 +0200 <geekosaur> speed. did you notice earlier when I mentioned the extra code to check kernel ABI versions?
2024-09-21 22:17:11 +0200 <tomsmeding> (apart from the latter possibly being a little slower)
2024-09-21 22:16:58 +0200 <tomsmeding> I dunno, maybe. But if so, then what's the difference (to go) between a syscall and a libc function that wraps that syscall?
2024-09-21 22:16:44 +0200 <geekosaur> similarly to what ghc's RTS does with `safe` calls
2024-09-21 22:16:27 +0200 <geekosaur> right, I assume it offloads the actual call to a thread that isn't part of the scheduler so it can safely block
2024-09-21 22:16:23 +0200 <tomsmeding> eventually there is some code in go's stdlib or RTS that does the actual syscall, be it directly or through libc
2024-09-21 22:16:15 +0200merijn(~merijn@204-220-045-062.dynamic.caiway.nl)
2024-09-21 22:15:36 +0200 <tomsmeding> of course, but we're talking about how said go function is implemented
2024-09-21 22:15:18 +0200 <geekosaur> right, but you're not supposed to do either, you use the go function which offloads the call (similarly to Haskell's `safe`) so it doesn't block the scheduler
2024-09-21 22:14:49 +0200 <tomsmeding> (surely?)
2024-09-21 22:14:36 +0200 <tomsmeding> well, some are, but then the libc call would also be
2024-09-21 22:14:05 +0200 <tomsmeding> but a syscall is also uninterruptible
2024-09-21 22:14:01 +0200 <geekosaur> blocking syscalls would be a problem, imagine that a go syscall is Haskell's `unsafe`
2024-09-21 22:13:49 +0200 <tomsmeding> libc is just C code, which is just additional work that happens before and after the syscall -- which itself is just work that happens on a different privilege level
2024-09-21 22:13:41 +0200 <tuxpaint> it becomes a task that is uninterruptable by the go runtime, since the syscall is happening outside of the runtime, it has to make the most conservative assumptions possible
2024-09-21 22:13:18 +0200 <tomsmeding> tuxpaint: that sounds weird to me; libc surely doesn't lock up the runtime any more than a system call does. The only reason would be that libc has overhead -- which I can accept -- but that would still just be "doing syscalls directly is faster".
2024-09-21 22:11:50 +0200 <tomsmeding> note that buffers are not flushed by the RTS upon exit(3)
2024-09-21 22:11:37 +0200 <tomsmeding> https://paste.tomsmeding.com/WzVl8hRp
2024-09-21 22:11:24 +0200 <tuxpaint> it's not about absolute speed, it locks up the runtime and would make the language unusable
2024-09-21 22:11:03 +0200 <geekosaur> (more likely they watch the commits list very closely so they have the necessary library changes by the time it's released)
2024-09-21 22:10:37 +0200 <tomsmeding> use the capi style though, for the reasons monochrom mentioned
2024-09-21 22:10:33 +0200 <tuxpaint> if you do syscalls through libc you have to do calls which fuck with the go scheduler.
2024-09-21 22:10:25 +0200 <tuxpaint> yep!
2024-09-21 22:10:21 +0200 <tomsmeding> tuxpaint: seems we have a workaround? :p
2024-09-21 22:10:12 +0200 <EvanR> move fast break things
2024-09-21 22:09:58 +0200athan(~athan@syn-098-153-145-140.biz.spectrum.com) (Quit: Konversation terminated!)
2024-09-21 22:09:41 +0200 <geekosaur> so they can't update a kernel without auditing the kernel/libc interface and updating their go libs, or they get random crashes
2024-09-21 22:09:39 +0200 <tomsmeding> ah good, capi vs ccall import doesn't make a difference in timing
2024-09-21 22:09:00 +0200 <geekosaur> no, they just want absolute speed and went the accursedUnutterablePerformIO route
2024-09-21 22:08:22 +0200 <tuxpaint> and yeah, it's google. they probably need more jobs for the employees they already have :)
2024-09-21 22:08:11 +0200 <monochrom> OK heh :)