2024/05/16

Newest at the top

2024-05-16 19:10:25 +0200 <ski> .. but my unintended usage of view patterns, above, doesn't support this style of defining `fib'
2024-05-16 19:10:24 +0200 <Guest13> what does memoArray do again?
2024-05-16 19:09:55 +0200 <ski> (memoArray (0,n) -> fib) n = fib (n-1) + fib (n-2)
2024-05-16 19:09:51 +0200 <ski> (memoArray (0,n) -> fib) 1 = 1
2024-05-16 19:09:48 +0200 <ski> (memoArray (0,n) -> fib) 0 = 0
2024-05-16 19:09:35 +0200 <ski> it would perhaps be even more fun, if we could write
2024-05-16 19:09:17 +0200 <ski> well, we're also avoiding wrapping the whole `\case ...' in brackets. so when we break that over multiple lines in the source file, we don't need a closing bracket at the end, that may look a bit unclear which opening bracket it is matching, multiple lines up
2024-05-16 19:08:58 +0200 <Guest13> you are saying that to get x in (f -> x) = y you need to call f on y
2024-05-16 19:08:38 +0200 <Guest13> I think I get it now though
2024-05-16 19:08:31 +0200 <Guest13> I understood the below one immediately but the top was super confusing lol
2024-05-16 19:08:08 +0200 <Guest13> lol
2024-05-16 19:08:04 +0200 <ski> cuteness
2024-05-16 19:07:59 +0200 <Guest13> is there a reason to phrase it like that?
2024-05-16 19:07:36 +0200 <ski> fib = memoArray (0,n) (\case 0 -> 0; 1 -> 1; n -> fib (n-1) + fib (n-2))
2024-05-16 19:07:26 +0200 <ski> this is actually the same thing as
2024-05-16 19:07:20 +0200 <ski> (memoArray (0,n) -> fib) = \case 0 -> 0; 1 -> 1; n -> fib (n-1) + fib (n-2)
2024-05-16 19:07:11 +0200 <ski> so, in my example
2024-05-16 19:07:02 +0200 <ski> (input `x', matched against the view-pattern `(f -> y)', will call `f' on the input `x', and match the result of that to the pattern `y')
2024-05-16 19:07:01 +0200 <Guest13> I see how applying f to both sides does that
2024-05-16 19:06:32 +0200 <ski> y = f x
2024-05-16 19:06:28 +0200 <ski> amounts to the same thing as
2024-05-16 19:06:23 +0200 <ski> (f -> y) = x
2024-05-16 19:06:19 +0200 <ski> or, more generally, we can say that
2024-05-16 19:05:55 +0200 <ski> (.. except that if `y' is a complex pattern, rather than a simple variable, then failure to match that pattern will cause the whole defining equation `foo (f -> y) = ...' to fail (trying the next defining equation instead), while with the `where'-version above, this doesn't happen)
2024-05-16 19:05:01 +0200 <ski> y = f x
2024-05-16 19:04:58 +0200 <ski> where
2024-05-16 19:04:56 +0200 <ski> foo x = ..y..
2024-05-16 19:04:49 +0200 <ski> can be refactored/rewritten as
2024-05-16 19:04:41 +0200 <Guest13> yeah
2024-05-16 19:04:36 +0200 <ski> foo (f -> y) = ..y..
2024-05-16 19:04:25 +0200 <ski> in general
2024-05-16 19:04:25 +0200 <Guest13> but not how the syntax reflects that
2024-05-16 19:04:22 +0200 <ski> oh
2024-05-16 19:04:17 +0200 <Guest13> I understand what it is doing
2024-05-16 19:03:56 +0200 <ski> that example makes sense to you ?
2024-05-16 19:03:31 +0200 <ski> this will call `reverse' on the input `[2,3,5,7]', before trying to match it with the pattern `x:_'. so we actually match the list `[7,5,3,2]' with the pattern `x:_', so `x' becomes `7'
2024-05-16 19:02:54 +0200 <lambdabot> 7
2024-05-16 19:02:52 +0200 <ski> > let last (reverse -> x:_) = x in last [2,3,5,7]
2024-05-16 19:02:31 +0200 <ski> e.g.
2024-05-16 19:02:24 +0200 <ski> my use of the view pattern above is rather unusual .. normally view patterns are used in function (formal) parameter patterns
2024-05-16 19:02:12 +0200 <Guest13> we are assigning a function to the left
2024-05-16 19:01:50 +0200 <Guest13> I don't understand the assignment
2024-05-16 19:01:50 +0200 <ski> `(<expr> -> <pat>)' is a, so-called, view pattern
2024-05-16 19:01:23 +0200 <ski> Guest13 : well, basically we just splice a memoization/caching lookup inbetween each recursive call
2024-05-16 19:01:13 +0200 <Guest13> ((!) . tabulate (0,n) -> fib) = \case 0 -> 0; 1 -> 1; n -> fib (n-1) + fib (n-2) I don't understand
2024-05-16 19:00:42 +0200 <ski> Guest13 : "bottom up is usually better surely","if you can do it" -- depends. if you know which results will be needed, beforehand, i'll probably be a little more efficient, i suppose. but if there may be large swathes of subresults that may not actually be needed, then it's hard to avoid computing them anyway with bottom-up, so in that case you may be doing quite a bit more work than for top-down
2024-05-16 19:00:39 +0200 <Guest13> not sure I understand this one
2024-05-16 18:58:37 +0200 <lambdabot> 144
2024-05-16 18:58:35 +0200 <ski> > let memoFib n | n >= 0 = fib n where (memoArray (0,n) -> fib) = \case 0 -> 0; 1 -> 1; n -> fib (n-1) + fib (n-2) in memoFib 12 -- same thing, just slightly clearer
2024-05-16 18:58:19 +0200 <lambdabot> Defined.